Matrix Rotation 90 degrees in clockwise direction

                                      Problem: Matrix Rotation

Rotate a n*n matrix  90 degrees in clockwise direction.

Input:
Matrix:
 1  2  3
 4  5  6
 7  8  9
Output:
 7  4  1 
 8  5  2 
 9  6  3

Approach: The idea behind this is to first find the transpose of given matrix. Transpose of above matrix is:

1  4  7

2  5  8

3  6  9

Now, we have to swap same row elements of first column to its last column. In above example,

We are swapping elements 1 to 7, 2 to 8 and 3 to 9. The middle row of matrix is same as it is. 

So, the condition we are using for transposing is:

for i in range(len(matrix)):
    for j in range(i,len(matrix)):

        m[i][j], m[j][i] = m[j][i], m[i][j] 

Now, after transposing we are again doing swapping for the perfect answer.

for i in range(len(matrix):
    for j in range(int(len(matrix)/2)):
        m[i][j], m[i][len(matrix)-1-j] = m[i][len(matrix)-1-j], m[i][j]

Solution:

import numpy as np

row = int(input("enter no of rows:"))
col = int(input("enter no of columns:"))
n = list(map(str, input().split(" ")))

m = np.array(n).reshape(row,col)
n= len(m)

#matrix transpose

for i in range(n):
    for j in range(i,n):
        m[i][j], m[j][i] = m[j][i], m[i][j]

#matrix rotation 90degrees clockwise

for i in range(n):
    for j in range(int(n/2)):
        m[i][j], m[i][n-1-j] = m[i][n-1-j], m[i][j]

print(m)